| A |
B |
The moving source is illustrated in an animation in: http://folk.ntnu.no/stoylen/strainrate/Ultrasound/index.html#Doppler |
![]() Thanks to Hon Chen Eng of University of Toledo who pointed out an inconsistency in the original illustration and showed a better way of illustrating the Doppler effect in this image. |
| An observer (blue) moving
towards a stationary wavesource with the velocity: The change
in frequency, the Doppler shift is: |
If
the source moves toward a stationary observer In
the time the wave
moves one wavelength, the source moves the
distance:
The
motion
of the wave and the motion of the source happen during the same time
interval:
The distance from the next wave emitted from the new position of the source (small dotted red circle) to the observer (blue) is shortened by Thus:
The change in frequency, the Doppler shift is: If v << c, then: and:
|
| Phase analysis. If the waveform is treated as a sine
curve, every
point on the curve corresponds to an angle, and the phase of the point
in the curve can be described by this angle; the phase angle |
However,
from the diagram at the top, it is evident that by sampling the
waveform only once, the phase is ambiguous, it is not possible to
separate the phase of point a from point b. The two points are
separated by a quarter of a wavelentgh, or 90° ( |
| Two pulses sent toward a scatterer with a time delay t2 - t1 = 1/PRF. Given that the scatterer has a velocity, it will have moved a distance, d, that is a function of the velocity and the time (d = v x t). Thus, pulse 2 travels a longer (or shorter) distance equal to d with the speed of sound, c, before it is reflected. | During the time pulse2 has travelled the
distance d to the new position of the scatterer and back to the point
of the reflection of pulse 1, i.e. a distance 2d pulse 1 has
travelled the same distance away from the reflection point. (The
scatterer will have travelled further, but this
is not
relevant). Thus the diasplacement of the waveform of pulse 2
relative to pulse 1, is 2d. This corresponds to a phase shift from
pulse 1 to pulse 2 of |
By sampling the two pulses simultaneously at two timepoints, as shown in the previous illustration, the phase of each pulse can be determined. The analysis f hte relative positions of all four points is done by autocorrelation, a quick (and dirty?) method that allows online computation. |
|
As
descibed above, a pulse has a certein bandwidth,
describing the frequency content of the pulse. In spectral analysis,
this will give a spectrum of a certain width, corresponding to the
velocity distribution of flow velocities. In phase analysis, this will
correspont to a certain distribution of phase angles as illustrated.
Autocorrelation, however, will only result in the average phase angle.
|
In
the case of stationary noise (clutter) as f.i. reverberations, the
autocorrelation will result in an average phase angle that is in
between the signal and the noise. The clutter noise will have to be
removed by a low velocity filter in order to avoid severe
underestimation of flow velocities. |
| Left: two systolic velocity curves with velocities somewhat arbitrarily chosen, but within normal range, and with a fairly normal shape. The values on the cyan curve is two thirds of the red one, and both have peak velocity at 0.05 sec. Left: strain rate curves calculated from the velocity curves on the right side. Assuming an initial distance between the points of the two velocity curves of 2.5 cm, again a realistic distance for the velocity difference. Lagrangian strain (yellow) is derived by dividing the velocity difference at each time point by the initial distance. This results in a simple inversion of the velocity difference, in a different scale, and with minimum value (maximum absolute) at 0.05 sec. Eulerian strain (green curve) is obtained by dividing with a strain length that decreases by the time interval times the velocity difference. In this case the differences between the curves is evident, and the minimum value (maximum absolute) of Eulerian strain rate is reached at 0.25 seconds. | |
| Strain measured by integration
of the strain rate curves in the figure above. It is evident that the total systolic strain is about 6% higher (absolute values) by Eulerian strain rate. |
Strain as a function of integrated strain
rate. Integration of velocity gradient leads to Eulerian strain (dotted
line: identity). Lagrangian strain will give values that lies above
Eulerian strain, i.e. negative values are lower in absolute values,
while
positive values are higher as one integrates from zero.
(After Hans Torp by permission). |
Strain curves by the two methods: Grey as they appear by direct integration of the velocity gradient (strain rate), i.e. Eulerian or "natural" strain. Black the Lagrangian strain by appying the correction formula below. (After Hans Torp by permission). |
| Incompressibility. The figure shows simultaneous longitudinal shortening or compression, as well as thickening or expansion in the two transverse directions. If the cylinder is incompressible, the sum of the longitudinal and the two transverse strains will be zero. | The cube increases its length along the x axis (positive strain), while the x and y lengths decreases (negative strain), in such a way as to keep the volume constant: |
| As
the outer contour remains constant during systole as discussed in long
axis function, this means that as the ventricle shortens, the wall has
to thicken inwards. When the left ventricle shortens in systole, the
total volume is reduced by the volume of the cylinder shown in
grey. |
The
left ventricle seen as a half
ellipsoid with apex wall thickness half the wall thickness at the base.
For the left ventricle, the short axis cross section may be
assumed circular, and the short axis radii thus equal (r = d/2), while
the long axis radius is equal to the length of the half
ellipsoid, l. Wall thickness at the base; w is the difference between
outer and inner radius (or two
wall thicknesses is the difference between outer and inner diameter): do
= di + 2W (or inner diameter di = do - 2W). Wall thickness decreases toward the apex, for simplified calculation (to avoid recurion) it is assumed to be zero. li = lo = l The volume of a general ellipsoid is 4/3 * Total or outer volume Vt = 2/3* Midwall diameter is dm = di + W and midwall circumference is cm = dm * |
| Diastole |
Systole |
|
| Total volume | Vtd = 2/3* pi * (do/2)2 * ld | Vts
= 2/3* |
| Cavity volume diastole |
Vcd
= 2/3* |
|
| Wall volume |
Vw = Vwd = Vtd - Vcd | Vws = Vwd = Vw due to incompressibility |
| Cavity volume systole |
Vcs = Vts -Vw | |
| Stroke volume |
SV = Vcd - Vcs | |
| EF |
EF
= SV / Vcd With
an invariant outer diameter, this would equal (-Vtd * |
|
| Wall thickness |
Wd
= 1/2 (do - did) |
Ws
= Wd + Wd * WT |
| Fractional shortening |
FS
= (did - dis) / dis |
| Invariant outer diameter |
5% systolic reduction in outer diameter |
|
| Stroke
volume |
44 ml |
72 ml |
| EF |
33% |
58% |
| Wall
thickening |
27% |
49% |
| Midwall
shortening |
4% |
14% |
| Fractional
(inner diameter) shortening |
9% |
27% |

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Editor: Depertment head, Contact address: isb-post@medisin.ntnu.no, Updated: XXX